Description
A peak element in a 2D grid is an element that is strictly greater than all of its adjacent neighbors to the left, right, top, and bottom.
Given a 0-indexed m x n matrix mat where no two adjacent cells are equal, find any peak element mat[i][j] and return the length 2 array [i,j].
You may assume that the entire matrix is surrounded by an outer perimeter with the value -1 in each cell.
You must write an algorithm that runs in O(m log(n)) or O(n log(m)) time.
Example 1:

Input: mat = [[1,4],[3,2]] Output: [0,1] Explanation: Both 3 and 4 are peak elements so [1,0] and [0,1] are both acceptable answers.
Example 2:

Input: mat = [[10,20,15],[21,30,14],[7,16,32]] Output: [1,1] Explanation: Both 30 and 32 are peak elements so [1,1] and [2,2] are both acceptable answers.
Constraints:
m == mat.lengthn == mat[i].length1 <= m, n <= 5001 <= mat[i][j] <= 105- No two adjacent cells are equal.
Solution
Python3
class Solution:
def findPeakGrid(self, mat: List[List[int]]) -> List[int]:
rows, cols = len(mat), len(mat[0])
top = 0
bottom = rows - 1
while bottom > top:
mid = (top + bottom) // 2
if max(mat[mid]) > max(mat[mid+1]):
bottom = mid
else:
top = mid + 1
return [bottom, mat[bottom].index(max(mat[bottom]))]