Description
You are given an array of k
linked-lists lists
, each linked-list is sorted in ascending order.
Merge all the linked-lists into one sorted linked-list and return it.
Β
Example 1:
Input: lists = [[1,4,5],[1,3,4],[2,6]] Output: [1,1,2,3,4,4,5,6] Explanation: The linked-lists are: [ 1->4->5, 1->3->4, 2->6 ] merging them into one sorted list: 1->1->2->3->4->4->5->6
Example 2:
Input: lists = [] Output: []
Example 3:
Input: lists = [[]] Output: []
Β
Constraints:
k == lists.length
0 <= k <= 104
0 <= lists[i].length <= 500
-104 <= lists[i][j] <= 104
lists[i]
is sorted in ascending order.- The sum of
lists[i].length
will not exceed104
.
Solution
Python3
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Node:
def __init__(self, val, l):
self.val = val
self.l = l
def __lt__(self, other):
return self.val < other.val
class Solution:
def mergeKLists(self, lists: List[Optional[ListNode]]) -> Optional[ListNode]:
pq = []
for l in lists:
if l:
heappush(pq, Node(l.val, l.next))
res = curr = ListNode(-1)
while pq:
node = heappop(pq)
val, rem = node.val, node.l
curr.next = ListNode(val)
curr = curr.next
if rem:
heappush(pq, Node(rem.val, rem.next))
return res.next