Description
You are given an array of k
linked-lists lists
, each linked-list is sorted in ascending order.
Merge all the linked-lists into one sorted linked-list and return it.
Β
Example 1:
Input: lists = [[1,4,5],[1,3,4],[2,6]] Output: [1,1,2,3,4,4,5,6] Explanation: The linked-lists are: [ 1->4->5, 1->3->4, 2->6 ] merging them into one sorted list: 1->1->2->3->4->4->5->6
Example 2:
Input: lists = [] Output: []
Example 3:
Input: lists = [[]] Output: []
Β
Constraints:
k == lists.length
0 <= k <= 104
0 <= lists[i].length <= 500
-104 <= lists[i][j] <= 104
lists[i]
is sorted in ascending order.- The sum of
lists[i].length
will not exceed104
.
Solution
Python3
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def mergeKLists(self, lists: List[Optional[ListNode]]) -> Optional[ListNode]:
if not lists: return None
res = curr = ListNode(-1)
pq = []
for index, head in enumerate(lists):
if head:
heappush(pq, (head.val, index))
while pq:
val, index = heappop(pq)
curr.next = lists[index]
curr = curr.next
lists[index] = lists[index].next
if lists[index]:
heappush(pq, (lists[index].val, index))
return res.next