Description
Given a binary array nums
, you should delete one element from it.
Return the size of the longest non-empty subarray containing only 1
's in the resulting array. Return 0
if there is no such subarray.
Example 1:
Input: nums = [1,1,0,1] Output: 3 Explanation: After deleting the number in position 2, [1,1,1] contains 3 numbers with value of 1's.
Example 2:
Input: nums = [0,1,1,1,0,1,1,0,1] Output: 5 Explanation: After deleting the number in position 4, [0,1,1,1,1,1,0,1] longest subarray with value of 1's is [1,1,1,1,1].
Example 3:
Input: nums = [1,1,1] Output: 2 Explanation: You must delete one element.
Constraints:
1 <= nums.length <= 105
nums[i]
is either0
or1
.
Solution
Python3
class Solution:
def longestSubarray(self, nums: List[int]) -> int:
k = 1
i = res = 0
for j, x in enumerate(nums):
if x == 0:
k -= 1
while k < 0:
if nums[i] == 0:
k += 1
i += 1
res = max(res, j - i)
return res