Description
You are given two 0-indexed integer arrays player1 and player2, representing the number of pins that player 1 and player 2 hit in a bowling game, respectively.
The bowling game consists of n turns, and the number of pins in each turn is exactly 10.
Assume a player hits xi pins in the ith turn. The value of the ith turn for the player is:
2xiif the player hits 10 pins in either (i - 1)th or (i - 2)th turn.- Otherwise, it is
xi.
The score of the player is the sum of the values of their n turns.
Return
- 1 if the score of player 1 is more than the score of player 2,
- 2 if the score of player 2 is more than the score of player 1, and
- 0 in case of a draw.
Example 1:
Input: player1 = [5,10,3,2], player2 = [6,5,7,3]
Output: 1
Explanation:
The score of player 1 is 5 + 10 + 2*3 + 2*2 = 25.
The score of player 2 is 6 + 5 + 7 + 3 = 21.
Example 2:
Input: player1 = [3,5,7,6], player2 = [8,10,10,2]
Output: 2
Explanation:
The score of player 1 is 3 + 5 + 7 + 6 = 21.
The score of player 2 is 8 + 10 + 2*10 + 2*2 = 42.
Example 3:
Input: player1 = [2,3], player2 = [4,1]
Output: 0
Explanation:
The score of player1 is 2 + 3 = 5.
The score of player2 is 4 + 1 = 5.
Example 4:
Input: player1 = [1,1,1,10,10,10,10], player2 = [10,10,10,10,1,1,1]
Output: 2
Explanation:
The score of player1 is 1 + 1 + 1 + 10 + 2*10 + 2*10 + 2*10 = 73.
The score of player2 is 10 + 2*10 + 2*10 + 2*10 + 2*1 + 2*1 + 1 = 75.
Constraints:
n == player1.length == player2.length1 <= n <= 10000 <= player1[i], player2[i] <= 10
Solution
Python3
class Solution:
def isWinner(self, player1: List[int], player2: List[int]) -> int:
def getScore(s):
count = 0
for i in range(len(s)):
double = False
if i - 1 >= 0 and s[i - 1] == 10:
double = True
if i - 2 >= 0 and s[i - 2] == 10:
double = True
if double:
count += s[i] * 2
else:
count += s[i]
return count
s1 = getScore(player1)
s2 = getScore(player2)
if s1 == s2:
return 0
elif s1 > s2:
return 1
else:
return 2