Description
You are given an integer array nums
. The absolute sum of a subarray [numsl, numsl+1, ..., numsr-1, numsr]
is abs(numsl + numsl+1 + ... + numsr-1 + numsr)
.
Return the maximum absolute sum of any (possibly empty) subarray of nums
.
Note that abs(x)
is defined as follows:
- If
x
is a negative integer, thenabs(x) = -x
. - If
x
is a non-negative integer, thenabs(x) = x
.
Example 1:
Input: nums = [1,-3,2,3,-4] Output: 5 Explanation: The subarray [2,3] has absolute sum = abs(2+3) = abs(5) = 5.
Example 2:
Input: nums = [2,-5,1,-4,3,-2] Output: 8 Explanation: The subarray [-5,1,-4] has absolute sum = abs(-5+1-4) = abs(-8) = 8.
Constraints:
1 <= nums.length <= 105
-104 <= nums[i] <= 104
Solution
Python3
class Solution:
def maxAbsoluteSum(self, nums: List[int]) -> int:
mmax = mmin = s = 0
for num in nums:
s += num
mmax = max(mmax, s)
mmin = min(mmin, s)
return mmax - mmin