Description
An array is considered special if every pair of its adjacent elements contains two numbers with different parity.
You are given an array of integer nums and a 2D integer matrix queries, where for queries[i] = [fromi, toi] your task is to check that subarray nums[fromi..toi] is special or not.
Return an array of booleans answer such that answer[i] is true if nums[fromi..toi] is special.
Β
Example 1:
Input: nums = [3,4,1,2,6], queries = [[0,4]]
Output: [false]
Explanation:
The subarray is [3,4,1,2,6]. 2 and 6 are both even.
Example 2:
Input: nums = [4,3,1,6], queries = [[0,2],[2,3]]
Output: [false,true]
Explanation:
- The subarray is [4,3,1]. 3 and 1 are both odd. So the answer to this query isfalse.
- The subarray is [1,6]. There is only one pair:(1,6)and it contains numbers with different parity. So the answer to this query istrue.
Β
Constraints:
- 1 <= nums.length <= 105
- 1 <= nums[i] <= 105
- 1 <= queries.length <= 105
- queries[i].length == 2
- 0 <= queries[i][0] <= queries[i][1] <= nums.length - 1
Solution
Python3
class Solution:
    def isArraySpecial(self, nums: List[int], queries: List[List[int]]) -> List[bool]:
        N = len(nums)
        A = [0] * N
        A[0] = 1
        res = []
 
        for i in range(1, N):
            v = 1 if nums[i - 1] % 2 != nums[i] % 2 else 0
            A[i] += v + A[i - 1]
        for a, b in queries:
            res.append(A[b] - A[a] == (b - a))
        
        return res