Description
There is a programming language with only four operations and one variable X:
- ++Xand- X++increments the value of the variable- Xby- 1.
- --Xand- X--decrements the value of the variable- Xby- 1.
Initially, the value of X is 0.
Given an array of strings operations containing a list of operations, return the final value of X after performing all the operations.
Example 1:
Input: operations = ["--X","X++","X++"] Output: 1 Explanation: The operations are performed as follows: Initially, X = 0. --X: X is decremented by 1, X = 0 - 1 = -1. X++: X is incremented by 1, X = -1 + 1 = 0. X++: X is incremented by 1, X = 0 + 1 = 1.
Example 2:
Input: operations = ["++X","++X","X++"] Output: 3 Explanation: The operations are performed as follows: Initially, X = 0. ++X: X is incremented by 1, X = 0 + 1 = 1. ++X: X is incremented by 1, X = 1 + 1 = 2. X++: X is incremented by 1, X = 2 + 1 = 3.
Example 3:
Input: operations = ["X++","++X","--X","X--"] Output: 0 Explanation: The operations are performed as follows: Initially, X = 0. X++: X is incremented by 1, X = 0 + 1 = 1. ++X: X is incremented by 1, X = 1 + 1 = 2. --X: X is decremented by 1, X = 2 - 1 = 1. X--: X is decremented by 1, X = 1 - 1 = 0.
Constraints:
- 1 <= operations.length <= 100
- operations[i]will be either- "++X",- "X++",- "--X", or- "X--".
Solution
Python3
class Solution:
    def finalValueAfterOperations(self, operations: List[str]) -> int:
        res = 0
        
        for o in operations:
            if o == 'X++' or o == '++X':
                res += 1
            else:
                res -= 1
        
        return res