Description
Given a list of dominoes
, dominoes[i] = [a, b]
is equivalent to dominoes[j] = [c, d]
if and only if either (a == c
and b == d
), or (a == d
and b == c
) - that is, one domino can be rotated to be equal to another domino.
Return the number of pairs (i, j)
for which 0 <= i < j < dominoes.length
, and dominoes[i]
is equivalent to dominoes[j]
.
Example 1:
Input: dominoes = [[1,2],[2,1],[3,4],[5,6]] Output: 1
Example 2:
Input: dominoes = [[1,2],[1,2],[1,1],[1,2],[2,2]] Output: 3
Constraints:
1 <= dominoes.length <= 4 * 104
dominoes[i].length == 2
1 <= dominoes[i][j] <= 9
Solution
Python3
class Solution:
def numEquivDominoPairs(self, A: List[List[int]]) -> int:
n = len(A)
mp = collections.defaultdict(int)
def make(A):
return (min(A), max(A))
res = 0
for i in range(n):
m = make(A[i])
res += mp[m]
mp[m] += 1
return res