Description
You are given an integer n and an integer start.
Define an array nums where nums[i] = start + 2 * i (0-indexed) and n == nums.length.
Return the bitwise XOR of all elements of nums.
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Example 1:
Input: n = 5, start = 0 Output: 8 Explanation: Array nums is equal to [0, 2, 4, 6, 8] where (0 ^ 2 ^ 4 ^ 6 ^ 8) = 8. Where "^" corresponds to bitwise XOR operator.
Example 2:
Input: n = 4, start = 3 Output: 8 Explanation: Array nums is equal to [3, 5, 7, 9] where (3 ^ 5 ^ 7 ^ 9) = 8.
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Constraints:
- 1 <= n <= 1000
- 0 <= start <= 1000
- n == nums.length
Solution
Python3
class Solution:
    def xorOperation(self, n: int, start: int) -> int:
        
        ans = start
        
        for i in range(1,n):
            ans ^= start+2*i
        
        return ans