Description
Given an array intervals
where intervals[i] = [li, ri]
represent the interval [li, ri)
, remove all intervals that are covered by another interval in the list.
The interval [a, b)
is covered by the interval [c, d)
if and only if c <= a
and b <= d
.
Return the number of remaining intervals.
Example 1:
Input: intervals = [[1,4],[3,6],[2,8]] Output: 2 Explanation: Interval [3,6] is covered by [2,8], therefore it is removed.
Example 2:
Input: intervals = [[1,4],[2,3]] Output: 1
Constraints:
1 <= intervals.length <= 1000
intervals[i].length == 2
0 <= li < ri <= 105
- All the given intervals are unique.
Solution
Python3
class Solution:
def removeCoveredIntervals(self, intervals: List[List[int]]) -> int:
res = right = 0
intervals.sort(key = lambda x:(x[0],-x[1]))
for start,end in intervals:
res += end > right
right = max(right, end)
return res