Description
Given an array of strings words
, return the first palindromic string in the array. If there is no such string, return an empty string ""
.
A string is palindromic if it reads the same forward and backward.
Example 1:
Input: words = ["abc","car","ada","racecar","cool"] Output: "ada" Explanation: The first string that is palindromic is "ada". Note that "racecar" is also palindromic, but it is not the first.
Example 2:
Input: words = ["notapalindrome","racecar"] Output: "racecar" Explanation: The first and only string that is palindromic is "racecar".
Example 3:
Input: words = ["def","ghi"] Output: "" Explanation: There are no palindromic strings, so the empty string is returned.
Constraints:
1 <= words.length <= 100
1 <= words[i].length <= 100
words[i]
consists only of lowercase English letters.
Solution
Python3
class Solution:
def firstPalindrome(self, words: List[str]) -> str:
def isPal(word):
N = len(word)
i, j = 0, N - 1
while i <= j and word[i] == word[j]:
i += 1
j -= 1
return i >= j
for x in words:
if isPal(x):
return x
return ""