Description
Given an array of strings words, return the first palindromic string in the array. If there is no such string, return an empty string "".
A string is palindromic if it reads the same forward and backward.
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Example 1:
Input: words = ["abc","car","ada","racecar","cool"] Output: "ada" Explanation: The first string that is palindromic is "ada". Note that "racecar" is also palindromic, but it is not the first.
Example 2:
Input: words = ["notapalindrome","racecar"] Output: "racecar" Explanation: The first and only string that is palindromic is "racecar".
Example 3:
Input: words = ["def","ghi"] Output: "" Explanation: There are no palindromic strings, so the empty string is returned.
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Constraints:
- 1 <= words.length <= 100
- 1 <= words[i].length <= 100
- words[i]consists only of lowercase English letters.
Solution
Python3
class Solution:
    def firstPalindrome(self, words: List[str]) -> str:
        def isPal(word):
            N = len(word)
            i, j = 0, N - 1
 
            while i <= j and word[i] == word[j]:
                i += 1
                j -= 1
            
            return i >= j
 
        for x in words:
            if isPal(x):
                return x
                
        return ""