412. Fizz Buzz

Problem Link

Description

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Given an integer n, return a string array answer (1-indexed) where:

• answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
• answer[i] == "Fizz" if i is divisible by 3.
• answer[i] == "Buzz" if i is divisible by 5.
• answer[i] == i (as a string) if none of the above conditions are true.

 

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

 

Constraints:

• 1 <= n <= 104

Solution

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Python3

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        ans = []
        
        for i in range(1,n+1):
            if i%3 == 0 and i%5 == 0: ans.append("FizzBuzz")
            
            elif i%3 == 0: ans.append("Fizz")
                
            elif i%5 == 0: ans.append("Buzz")
            
            else:
                ans.append(str(i))
        
        return ans