Description
You are given an integer array nums. In one move, you can pick an index i where 0 <= i < nums.length and increment nums[i] by 1.
Return the minimum number of moves to make every value in nums unique.
The test cases are generated so that the answer fits in a 32-bit integer.
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Example 1:
Input: nums = [1,2,2] Output: 1 Explanation: After 1 move, the array could be [1, 2, 3].
Example 2:
Input: nums = [3,2,1,2,1,7] Output: 6 Explanation: After 6 moves, the array could be [3, 4, 1, 2, 5, 7]. It can be shown that it is impossible for the array to have all unique values with 5 or less moves.
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Constraints:
- 1 <= nums.length <= 105
- 0 <= nums[i] <= 105
Solution
Python3
class Solution:
    def minIncrementForUnique(self, nums: List[int]) -> int:
        N = len(nums)
        res = 0
        curr = -1
        nums.sort()
 
        for x in nums:
            if x > curr:
                curr = x
            else: # curr >= x
                res += curr - x + 1
                curr += 1
 
        return res