Description
A binary string is monotone increasing if it consists of some number of 0's (possibly none), followed by some number of 1's (also possibly none).
You are given a binary string s. You can flip s[i] changing it from 0 to 1 or from 1 to 0.
Return the minimum number of flips to make s monotone increasing.
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Example 1:
Input: s = "00110" Output: 1 Explanation: We flip the last digit to get 00111.
Example 2:
Input: s = "010110" Output: 2 Explanation: We flip to get 011111, or alternatively 000111.
Example 3:
Input: s = "00011000" Output: 2 Explanation: We flip to get 00000000.
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Constraints:
1 <= s.length <= 105s[i]is either'0'or'1'.
Solution
Python3
class Solution:
def minFlipsMonoIncr(self, s: str) -> int:
flipCount = oneCount = 0
for x in s:
if x == '0':
flipCount += 1
else:
oneCount += 1
flipCount = min(flipCount, oneCount)
return flipCount