Description
You are given an array of integers nums. Return the length of the longest subarray of nums which is either strictly increasing or strictly decreasing.
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Example 1:
Input: nums = [1,4,3,3,2]
Output: 2
Explanation:
The strictly increasing subarrays of nums are [1], [2], [3], [3], [4], and [1,4].
The strictly decreasing subarrays of nums are [1], [2], [3], [3], [4], [3,2], and [4,3].
Hence, we return 2.
Example 2:
Input: nums = [3,3,3,3]
Output: 1
Explanation:
The strictly increasing subarrays of nums are [3], [3], [3], and [3].
The strictly decreasing subarrays of nums are [3], [3], [3], and [3].
Hence, we return 1.
Example 3:
Input: nums = [3,2,1]
Output: 3
Explanation:
The strictly increasing subarrays of nums are [3], [2], and [1].
The strictly decreasing subarrays of nums are [3], [2], [1], [3,2], [2,1], and [3,2,1].
Hence, we return 3.
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Constraints:
1 <= nums.length <= 501 <= nums[i] <= 50
Solution
Python3
class Solution:
def longestMonotonicSubarray(self, nums: List[int]) -> int:
N = len(nums)
res = inc = dec = 1
for i in range(1, N):
if nums[i] > nums[i - 1]:
inc += 1
res = max(res, inc)
else:
inc = 1
if nums[i] < nums[i - 1]:
dec += 1
res = max(res, dec)
else:
dec = 1
return res