Description
Given a binary array nums, return the maximum number of consecutive 1's in the array.
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Example 1:
Input: nums = [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Example 2:
Input: nums = [1,0,1,1,0,1] Output: 2
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Constraints:
- 1 <= nums.length <= 105
- nums[i]is either- 0or- 1.
Solution
Python3
class Solution:
    def findMaxConsecutiveOnes(self, nums: List[int]) -> int:
        res = ones = 0
        
        for x in nums:
            if x == 0:
                ones = 0
            else:
                ones += 1
        
            res = max(res, ones)
        
        return res