Description
You are given a 0-indexed integer array nums of size n and a positive integer k.
We call an index i in the range k <= i < n - k good if the following conditions are satisfied:
- The kelements that are just before the indexiare in non-increasing order.
- The kelements that are just after the indexiare in non-decreasing order.
Return an array of all good indices sorted in increasing order.
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Example 1:
Input: nums = [2,1,1,1,3,4,1], k = 2 Output: [2,3] Explanation: There are two good indices in the array: - Index 2. The subarray [2,1] is in non-increasing order, and the subarray [1,3] is in non-decreasing order. - Index 3. The subarray [1,1] is in non-increasing order, and the subarray [3,4] is in non-decreasing order. Note that the index 4 is not good because [4,1] is not non-decreasing.
Example 2:
Input: nums = [2,1,1,2], k = 2 Output: [] Explanation: There are no good indices in this array.
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Constraints:
- n == nums.length
- 3 <= n <= 105
- 1 <= nums[i] <= 106
- 1 <= k <= n / 2
Solution
Python3
class Solution:
    def goodIndices(self, nums: List[int], k: int) -> List[int]:
        N = len(nums)
        left = [0] * N
        right = [0] * N
        res = []
        
        for i in range(1, N):
            if nums[i] <= nums[i - 1]:
                left[i] = 1
        
            if nums[i] >= nums[i - 1]:
                right[i] = 1
 
        left = list(accumulate(left))
        right = list(accumulate(right))
 
        for i in range(k, N - k):
            L = left[i - 1] - left[i - k]
            R = right[i + k] - right[i + 1]
 
            if L == R == k - 1:
                res.append(i)
        
        return res