Description
Given two integer arrays nums1
and nums2
, sorted in non-decreasing order, return the minimum integer common to both arrays. If there is no common integer amongst nums1
and nums2
, return -1
.
Note that an integer is said to be common to nums1
and nums2
if both arrays have at least one occurrence of that integer.
Example 1:
Input: nums1 = [1,2,3], nums2 = [2,4] Output: 2 Explanation: The smallest element common to both arrays is 2, so we return 2.
Example 2:
Input: nums1 = [1,2,3,6], nums2 = [2,3,4,5] Output: 2 Explanation: There are two common elements in the array 2 and 3 out of which 2 is the smallest, so 2 is returned.
Constraints:
1 <= nums1.length, nums2.length <= 105
1 <= nums1[i], nums2[j] <= 109
- Both
nums1
andnums2
are sorted in non-decreasing order.
Solution
Python3
class Solution:
def getCommon(self, nums1: List[int], nums2: List[int]) -> int:
M, N = len(nums1), len(nums2)
j = 0
for i in range(M):
while j < N and nums2[j] < nums1[i]:
j += 1
if j == N: break
if nums1[i] == nums2[j]:
return nums1[i]
return -1