Description
Given two positive integers n
and x
.
Return the number of ways n
can be expressed as the sum of the xth
power of unique positive integers, in other words, the number of sets of unique integers [n1, n2, ..., nk]
where n = n1x + n2x + ... + nkx
.
Since the result can be very large, return it modulo 109 + 7
.
For example, if n = 160
and x = 3
, one way to express n
is n = 23 + 33 + 53
.
Example 1:
Input: n = 10, x = 2 Output: 1 Explanation: We can express n as the following: n = 32 + 12 = 10. It can be shown that it is the only way to express 10 as the sum of the 2nd power of unique integers.
Example 2:
Input: n = 4, x = 1 Output: 2 Explanation: We can express n in the following ways: - n = 41 = 4. - n = 31 + 11 = 4.
Constraints:
1 <= n <= 300
1 <= x <= 5
Solution
Python3
class Solution:
def numberOfWays(self, n: int, x: int) -> int:
M = 10 ** 9 + 7
base = 1
dp = [0] * (n + 1)
dp[0] = 1
while (curr := pow(base, x)) <= n:
for k in range(n, curr - 1, -1):
dp[k] += dp[k - curr]
dp[k] %= M
base += 1
return dp[n]