Description
Given a binary tree with the following rules:
root.val == 0- For any 
treeNode:- If 
treeNode.valhas a valuexandtreeNode.left != null, thentreeNode.left.val == 2 * x + 1 - If 
treeNode.valhas a valuexandtreeNode.right != null, thentreeNode.right.val == 2 * x + 2 
 - If 
 
Now the binary tree is contaminated, which means all treeNode.val have been changed to -1.
Implement the FindElements class:
FindElements(TreeNode* root)Initializes the object with a contaminated binary tree and recovers it.bool find(int target)Returnstrueif thetargetvalue exists in the recovered binary tree.
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Example 1:
Input ["FindElements","find","find"] [[[-1,null,-1]],[1],[2]] Output [null,false,true] Explanation FindElements findElements = new FindElements([-1,null,-1]); findElements.find(1); // return False findElements.find(2); // return True
Example 2:
Input ["FindElements","find","find","find"] [[[-1,-1,-1,-1,-1]],[1],[3],[5]] Output [null,true,true,false] Explanation FindElements findElements = new FindElements([-1,-1,-1,-1,-1]); findElements.find(1); // return True findElements.find(3); // return True findElements.find(5); // return False
Example 3:
Input ["FindElements","find","find","find","find"] [[[-1,null,-1,-1,null,-1]],[2],[3],[4],[5]] Output [null,true,false,false,true] Explanation FindElements findElements = new FindElements([-1,null,-1,-1,null,-1]); findElements.find(2); // return True findElements.find(3); // return False findElements.find(4); // return False findElements.find(5); // return True
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Constraints:
TreeNode.val == -1- The height of the binary tree is less than or equal to 
20 - The total number of nodes is between 
[1, 104] - Total calls of 
find()is between[1, 104] 0 <= target <= 106
Solution
Python3
# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class FindElements:
 
    def __init__(self, root: TreeNode):
        self.seen = set()
        
        def dfs(node: TreeNode, v: int) -> None:
            if not node: return
            
            node.val = v    
            self.seen.add(v)
            dfs(node.left, 2 * v + 1)
            dfs(node.right, 2 * v + 2)
            
        dfs(root, 0)
        
    def find(self, target: int) -> bool:
        return target in self.seen
 
 
# Your FindElements object will be instantiated and called as such:
# obj = FindElements(root)
# param_1 = obj.find(target)