Description
Given an integer array nums
of positive integers, return the average value of all even integers that are divisible by 3
.
Note that the average of n
elements is the sum of the n
elements divided by n
and rounded down to the nearest integer.
Example 1:
Input: nums = [1,3,6,10,12,15] Output: 9 Explanation: 6 and 12 are even numbers that are divisible by 3. (6 + 12) / 2 = 9.
Example 2:
Input: nums = [1,2,4,7,10] Output: 0 Explanation: There is no single number that satisfies the requirement, so return 0.
Constraints:
1 <= nums.length <= 1000
1 <= nums[i] <= 1000
Solution
Python3
class Solution:
def averageValue(self, nums: List[int]) -> int:
res = 0
count = 0
for x in nums:
if x % 3 == 0 and x % 2 == 0:
res += x
count += 1
if count == 0: return 0
return res // count