Description
Given a 0-indexed integer array nums of size n and two integers lower and upper, return the number of fair pairs.
A pair (i, j) is fair if:
0 <= i < j < n, andlower <= nums[i] + nums[j] <= upper
Β
Example 1:
Input: nums = [0,1,7,4,4,5], lower = 3, upper = 6 Output: 6 Explanation: There are 6 fair pairs: (0,3), (0,4), (0,5), (1,3), (1,4), and (1,5).
Example 2:
Input: nums = [1,7,9,2,5], lower = 11, upper = 11 Output: 1 Explanation: There is a single fair pair: (2,3).
Β
Constraints:
1 <= nums.length <= 105nums.length == n-109Β <= nums[i] <= 109-109Β <= lower <= upper <= 109
Solution
Python3
class Solution:
    def countFairPairs(self, nums: List[int], lower: int, upper: int) -> int:
        N = len(nums)
        nums.sort()
        res = 0
 
        for i, x in enumerate(nums):
            start = lower - x
            end = upper - x
 
            s = bisect_left(nums, start, 0, i)
            e = bisect_right(nums, end, 0, i)
            res += e - s
        
        return res