Description
Given an array of integers nums and an integer k. A continuous subarray is called nice if there are k odd numbers on it.
Return the number of nice sub-arrays.
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Example 1:
Input: nums = [1,1,2,1,1], k = 3 Output: 2 Explanation: The only sub-arrays with 3 odd numbers are [1,1,2,1] and [1,2,1,1].
Example 2:
Input: nums = [2,4,6], k = 1 Output: 0 Explanation: There are no odd numbers in the array.
Example 3:
Input: nums = [2,2,2,1,2,2,1,2,2,2], k = 2 Output: 16
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Constraints:
- 1 <= nums.length <= 50000
- 1 <= nums[i] <= 10^5
- 1 <= k <= nums.length
Solution
Python3
class Solution:
    def numberOfSubarrays(self, nums: List[int], k: int) -> int:
        N = len(nums)
        
        def atMost(k):
            res = odds = i = 0
            
            for j, x in enumerate(nums):
                odds += int(x & 1)
 
                while odds > k:
                    odds -= int(nums[i] & 1)
                    i += 1
                
                res += (j - i + 1)
 
            return res
        
        return atMost(k) - atMost(k - 1)