Description
Given an array of integers nums
containing n + 1
integers where each integer is in the range [1, n]
inclusive.
There is only one repeated number in nums
, return this repeated number.
You must solve the problem without modifying the array nums
and using only constant extra space.
Example 1:
Input: nums = [1,3,4,2,2] Output: 2
Example 2:
Input: nums = [3,1,3,4,2] Output: 3
Example 3:
Input: nums = [3,3,3,3,3] Output: 3
Constraints:
1 <= n <= 105
nums.length == n + 1
1 <= nums[i] <= n
- All the integers in
nums
appear only once except for precisely one integer which appears two or more times.
Follow up:
- How can we prove that at least one duplicate number must exist in
nums
? - Can you solve the problem in linear runtime complexity?
Solution
Python3
class Solution:
def findDuplicate(self, nums: List[int]) -> int:
slow, fast = nums[0], nums[nums[0]]
while slow != fast:
slow = nums[slow]
fast = nums[nums[fast]]
slow = 0
while slow != fast:
slow = nums[slow]
fast = nums[fast]
return slow