Description
Given the root
of a Binary Search Tree (BST), return the minimum absolute difference between the values of any two different nodes in the tree.
Example 1:

Input: root = [4,2,6,1,3] Output: 1
Example 2:

Input: root = [1,0,48,null,null,12,49] Output: 1
Constraints:
- The number of nodes in the tree is in the range
[2, 104]
. 0 <= Node.val <= 105
Note: This question is the same as 783: https://leetcode.com/problems/minimum-distance-between-bst-nodes/
Solution
Python3
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def getMinimumDifference(self, root: Optional[TreeNode]) -> int:
M = 10 ** 5 + 1
res = prev = M
def go(node):
nonlocal res, prev
if node.left:
go(node.left)
res = min(res, abs(node.val - prev))
prev = node.val
if node.right:
go(node.right)
go(root)
return res