Description
You are given a 0-indexed integer matrix grid and an integer k.
Return the number of submatrices that contain the top-left element of the grid, and have a sum less than or equal to k.
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Example 1:
 
Input: grid = [[7,6,3],[6,6,1]], k = 18 Output: 4 Explanation: There are only 4 submatrices, shown in the image above, that contain the top-left element of grid, and have a sum less than or equal to 18.
Example 2:
 
Input: grid = [[7,2,9],[1,5,0],[2,6,6]], k = 20 Output: 6 Explanation: There are only 6 submatrices, shown in the image above, that contain the top-left element of grid, and have a sum less than or equal to 20.
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Constraints:
- m == grid.length
- n == grid[i].length
- 1 <= n, m <= 1000
- 0 <= grid[i][j] <= 1000
- 1 <= k <= 109
Solution
Python3
class Solution:
    def countSubmatrices(self, grid: List[List[int]], k: int) -> int:
        rows, cols = len(grid), len(grid[0])
        res = 0
        
        for i in range(rows):
            for j in range(cols):
                if i >= 1: 
                    grid[i][j] += grid[i - 1][j]
                    
                if j >= 1:
                    grid[i][j] += grid[i][j - 1]
                
                if i >= 1 and j >= 1:
                    grid[i][j] -= grid[i - 1][j - 1]
                
                if grid[i][j] <= k:
                    res += 1
        
        return res