Description
You are given a string s and an integer k, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them, causing the left and the right side of the deleted substring to concatenate together.
We repeatedly make k duplicate removals on s until we no longer can.
Return the final string after all such duplicate removals have been made. It is guaranteed that the answer is unique.
Β
Example 1:
Input: s = "abcd", k = 2 Output: "abcd" Explanation: There's nothing to delete.
Example 2:
Input: s = "deeedbbcccbdaa", k = 3 Output: "aa" Explanation: First delete "eee" and "ccc", get "ddbbbdaa" Then delete "bbb", get "dddaa" Finally delete "ddd", get "aa"
Example 3:
Input: s = "pbbcggttciiippooaais", k = 2 Output: "ps"
Β
Constraints:
- 1 <= s.length <= 105
- 2 <= k <= 104
- sonly contains lowercase English letters.
Solution
Python3
class Solution:
    def removeDuplicates(self, s: str, k: int) -> str:
        stack = []
        
        for x in s:
            if stack and stack[-1][0] == x:
                _, cnt = stack.pop()
                stack.append((x, cnt + 1))
            else:
                stack.append((x, 1))
            
            if stack and stack[-1][1] == k:
                stack.pop()
            
        return "".join(x * cnt for x, cnt in stack)