Description
Given an array of integers arr, return true if the number of occurrences of each value in the array is unique or false otherwise.
Example 1:
Input: arr = [1,2,2,1,1,3] Output: true Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences.
Example 2:
Input: arr = [1,2] Output: false
Example 3:
Input: arr = [-3,0,1,-3,1,1,1,-3,10,0] Output: true
Constraints:
1 <= arr.length <= 1000-1000 <= arr[i] <= 1000
Solution
Python3
class Solution:
def uniqueOccurrences(self, arr: List[int]) -> bool:
return (cnt:= Counter(arr)) and len(set(cnt.values())) == len(cnt)Python
class Solution(object):
def uniqueOccurrences(self, arr):
"""
:type arr: List[int]
:rtype: bool
"""
res = []
lst= []
for i in arr:
if i not in res:
res.append(i)
for i in range(len(res)):
lst.append(arr.count(res[i]))
check_lst = []
for i in range(len(lst)):
if i>0:
if lst[i-1] == lst[i]:
break
check_lst.append(lst.count(lst[i]))
for i in check_lst:
if i>1:
return False
return True