Description
You are given a large integer represented as an integer array digits, where each digits[i] is the ith digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading 0's.
Increment the large integer by one and return the resulting array of digits.
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Example 1:
Input: digits = [1,2,3] Output: [1,2,4] Explanation: The array represents the integer 123. Incrementing by one gives 123 + 1 = 124. Thus, the result should be [1,2,4].
Example 2:
Input: digits = [4,3,2,1] Output: [4,3,2,2] Explanation: The array represents the integer 4321. Incrementing by one gives 4321 + 1 = 4322. Thus, the result should be [4,3,2,2].
Example 3:
Input: digits = [9] Output: [1,0] Explanation: The array represents the integer 9. Incrementing by one gives 9 + 1 = 10. Thus, the result should be [1,0].
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Constraints:
- 1 <= digits.length <= 100
- 0 <= digits[i] <= 9
- digitsdoes not contain any leading- 0's.
Solution
Python3
class Solution:
    def plusOne(self, digits: List[int]) -> List[int]:
        res = []
        digits[-1] += 1
        carry = 0
        
        for x in digits[::-1]:
            carry += x
            
            res.append(carry % 10)
            carry //= 10
        
        if carry > 0:
            res.append(carry)
        
        return res[::-1]