Description
Given two strings s and t, return the number of distinct subsequences of s which equals t.
The test cases are generated so that the answer fits on a 32-bit signed integer.
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Example 1:
Input: s = "rabbbit", t = "rabbit" Output: 3 Explanation: As shown below, there are 3 ways you can generate "rabbit" from s.rabbbitrabbbitrabbbit
Example 2:
Input: s = "babgbag", t = "bag" Output: 5 Explanation: As shown below, there are 5 ways you can generate "bag" from s.babgbagbabgbagbabgbagbabgbagbabgbag
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Constraints:
1 <= s.length, t.length <= 1000sandtconsist of English letters.
Solution
Python3
class Solution:
    def numDistinct(self, s: str, t: str) -> int:
        m, n = len(s), len(t)
        dp = [[0] * (m + 1) for _ in range(n + 1)]
        
        for j in range(m + 1):
            dp[0][j] = 1
        
        for i in range(n):
            for j in range(m):
                dp[i + 1][j + 1] = dp[i + 1][j]
                if t[i] == s[j]:
                    dp[i + 1][j + 1] += dp[i][j]
        
        return dp[n][m]