Description
Given two strings ransomNote
and magazine
, return true
if ransomNote
can be constructed by using the letters from magazine
and false
otherwise.
Each letter in magazine
can only be used once in ransomNote
.
Example 1:
Input: ransomNote = "a", magazine = "b" Output: false
Example 2:
Input: ransomNote = "aa", magazine = "ab" Output: false
Example 3:
Input: ransomNote = "aa", magazine = "aab" Output: true
Constraints:
1 <= ransomNote.length, magazine.length <= 105
ransomNote
andmagazine
consist of lowercase English letters.
Solution
Python3
class Solution:
def canConstruct(self, ransomNote: str, magazine: str) -> bool:
mp = collections.Counter(ransomNote)
n = len(mp)
for word in magazine:
mp[word] -= 1
if mp[word] == 0:
n -= 1
if n == 0: return True
return False