Description
You are given two arrays with positive integers arr1 and arr2.
A prefix of a positive integer is an integer formed by one or more of its digits, starting from its leftmost digit. For example, 123 is a prefix of the integer 12345, while 234 is not.
A common prefix of two integers a and b is an integer c, such that c is a prefix of both a and b. For example, 5655359 and 56554 have common prefixes 565 and 5655 while 1223 and 43456 do not have a common prefix.
You need to find the length of the longest common prefix between all pairs of integers (x, y) such that x belongs to arr1 and y belongs to arr2.
Return the length of the longest common prefix among all pairs. If no common prefix exists among them, return 0.
Example 1:
Input: arr1 = [1,10,100], arr2 = [1000] Output: 3 Explanation: There are 3 pairs (arr1[i], arr2[j]): - The longest common prefix of (1, 1000) is 1. - The longest common prefix of (10, 1000) is 10. - The longest common prefix of (100, 1000) is 100. The longest common prefix is 100 with a length of 3.
Example 2:
Input: arr1 = [1,2,3], arr2 = [4,4,4] Output: 0 Explanation: There exists no common prefix for any pair (arr1[i], arr2[j]), hence we return 0. Note that common prefixes between elements of the same array do not count.
Constraints:
1 <= arr1.length, arr2.length <= 5 * 1041 <= arr1[i], arr2[i] <= 108
Solution
Python3
class Solution:
def longestCommonPrefix(self, arr1: List[int], arr2: List[int]) -> int:
N, M = len(arr1), len(arr2)
res = 0
mp1 = set()
for x in arr1:
s = str(x)
curr = ""
for c in s:
curr += c
mp1.add(curr)
for x in arr2:
s = str(x)
for k in range(len(s)):
if s[0 : len(s) - k] in mp1:
res = max(res, len(s) - k)
return res