2278. Percentage of Letter in String

Problem Link

Description

---

Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.

 

Example 1:

Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.

Example 2:

Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.

 

Constraints:

• 1 <= s.length <= 100
• s consists of lowercase English letters.
• letter is a lowercase English letter.

Solution

---

Python3

class Solution:
    def percentageLetter(self, s: str, letter: str) -> int:
        n = len(s)
        c = s.count(letter)
        # print(n, c)
        return int(c / n * 100)