Description
You are given an integer array nums
.
A XOR triplet is defined as the XOR of three elements nums[i] XOR nums[j] XOR nums[k]
where i <= j <= k
.
Return the number of unique XOR triplet values from all possible triplets (i, j, k)
.
Β
Example 1:
Input: nums = [1,3]
Output: 2
Explanation:
The possible XOR triplet values are:
(0, 0, 0) β 1 XOR 1 XOR 1 = 1
(0, 0, 1) β 1 XOR 1 XOR 3 = 3
(0, 1, 1) β 1 XOR 3 XOR 3 = 1
(1, 1, 1) β 3 XOR 3 XOR 3 = 3
The unique XOR values are {1, 3}
. Thus, the output is 2.
Example 2:
Input: nums = [6,7,8,9]
Output: 4
Explanation:
The possible XOR triplet values are {6, 7, 8, 9}
. Thus, the output is 4.
Β
Constraints:
1 <= nums.length <= 1500
1 <= nums[i] <= 1500
Solution
Python3
class Solution:
def uniqueXorTriplets(self, nums: List[int]) -> int:
N = len(nums)
if N == 1: return 1
res = set()
nums.sort()
pairs = set()
for i in range(N):
for j in range(i):
pairs.add(nums[i] ^ nums[j])
for x in nums:
for pair in pairs:
res.add(x ^ pair)
return len(res)